encapsulate sdl_mixer stuff in #ifdef WITH_SDL_MIXER

[micropolis] / src / tk / tktrig.c

/* 
 * tkTrig.c --
 *
 *      This file contains a collection of trigonometry utility
 *      routines that are used by Tk and in particular by the
 *      canvas code.  It also has miscellaneous geometry functions
 *      used by canvases.
 *
 * Copyright 1992 Regents of the University of California.
 * Permission to use, copy, modify, and distribute this
 * software and its documentation for any purpose and without
 * fee is hereby granted, provided that the above copyright
 * notice appear in all copies.  The University of California
 * makes no representations about the suitability of this
 * software for any purpose.  It is provided "as is" without
 * express or implied warranty.
 */

#ifndef lint
static char rcsid[] = "$Header: /user6/ouster/wish/RCS/tkTrig.c,v 1.8 92/08/24 09:24:14 ouster Exp $ SPRITE (Berkeley)";
#endif

#include <stdio.h>
#include <math.h>
#include "tkconfig.h"
#include "tkcanvas.h"

#undef MIN
#define MIN(a,b) (((a) < (b)) ? (a) : (b))
#undef MAX
#define MAX(a,b) (((a) > (b)) ? (a) : (b))
#define PI 3.14159265358979323846
\f
/*
 *--------------------------------------------------------------
 *
 * TkLineToPoint --
 *
 *      Compute the distance from a point to a finite line segment.
 *
 * Results:
 *      The return value is the distance from the line segment
 *      whose end-points are *end1Ptr and *end2Ptr to the point
 *      given by *pointPtr.
 *
 * Side effects:
 *      None.
 *
 *--------------------------------------------------------------
 */

double
TkLineToPoint(end1Ptr, end2Ptr, pointPtr)
    double end1Ptr[2];          /* Coordinates of first end-point of line. */
    double end2Ptr[2];          /* Coordinates of second end-point of line. */
    double pointPtr[2];         /* Points to coords for point. */
{
    double x, y;

    /*
     * Compute the point on the line that is closest to the
     * point.  This must be done separately for vertical edges,
     * horizontal edges, and other edges.
     */

    if (end1Ptr[0] == end2Ptr[0]) {

        /*
         * Vertical edge.
         */

        x = end1Ptr[0];
        if (end1Ptr[1] >= end2Ptr[1]) {
            y = MIN(end1Ptr[1], pointPtr[1]);
            y = MAX(y, end2Ptr[1]);
        } else {
            y = MIN(end2Ptr[1], pointPtr[1]);
            y = MAX(y, end1Ptr[1]);
        }
    } else if (end1Ptr[1] == end2Ptr[1]) {

        /*
         * Horizontal edge.
         */

        y = end1Ptr[1];
        if (end1Ptr[0] >= end2Ptr[0]) {
            x = MIN(end1Ptr[0], pointPtr[0]);
            x = MAX(x, end2Ptr[0]);
        } else {
            x = MIN(end2Ptr[0], pointPtr[0]);
            x = MAX(x, end1Ptr[0]);
        }
    } else {
        double m1, b1, m2, b2;

        /*
         * The edge is neither horizontal nor vertical.  Convert the
         * edge to a line equation of the form y = m1*x + b1.  Then
         * compute a line perpendicular to this edge but passing
         * through the point, also in the form y = m2*x + b2.
         */

        m1 = (end2Ptr[1] - end1Ptr[1])/(end2Ptr[0] - end1Ptr[0]);
        b1 = end1Ptr[1] - m1*end1Ptr[0];
        m2 = -1.0/m1;
        b2 = pointPtr[1] - m2*pointPtr[0];
        x = (b2 - b1)/(m1 - m2);
        y = m1*x + b1;
        if (end1Ptr[0] > end2Ptr[0]) {
            if (x > end1Ptr[0]) {
                x = end1Ptr[0];
                y = end1Ptr[1];
            } else if (x < end2Ptr[0]) {
                x = end2Ptr[0];
                y = end2Ptr[1];
            }
        } else {
            if (x > end2Ptr[0]) {
                x = end2Ptr[0];
                y = end2Ptr[1];
            } else if (x < end1Ptr[0]) {
                x = end1Ptr[0];
                y = end1Ptr[1];
            }
        }
    }

    /*
     * Compute the distance to the closest point.
     */

    return hypot(pointPtr[0] - x, pointPtr[1] - y);
}
\f
/*
 *--------------------------------------------------------------
 *
 * TkLineToArea --
 *
 *      Determine whether a line lies entirely inside, entirely
 *      outside, or overlapping a given rectangular area.
 *
 * Results:
 *      -1 is returned if the line given by end1Ptr and end2Ptr
 *      is entirely outside the rectangle given by rectPtr.  0 is
 *      returned if the polygon overlaps the rectangle, and 1 is
 *      returned if the polygon is entirely inside the rectangle.
 *
 * Side effects:
 *      None.
 *
 *--------------------------------------------------------------
 */

int
TkLineToArea(end1Ptr, end2Ptr, rectPtr)
    double end1Ptr[2];          /* X and y coordinates for one endpoint
                                 * of line. */
    double end2Ptr[2];          /* X and y coordinates for other endpoint
                                 * of line. */
    double rectPtr[4];          /* Points to coords for rectangle, in the
                                 * order x1, y1, x2, y2.  X1 must be no
                                 * larger than x2, and y1 no larger than y2. */
{
    int inside1, inside2;

    /*
     * First check the two points individually to see whether they
     * are inside the rectangle or not.
     */

    inside1 = (end1Ptr[0] >= rectPtr[0]) && (end1Ptr[0] <= rectPtr[2])
            && (end1Ptr[1] >= rectPtr[1]) && (end1Ptr[1] <= rectPtr[3]);
    inside2 = (end2Ptr[0] >= rectPtr[0]) && (end2Ptr[0] <= rectPtr[2])
            && (end2Ptr[1] >= rectPtr[1]) && (end2Ptr[1] <= rectPtr[3]);
    if (inside1 != inside2) {
        return 0;
    }
    if (inside1 & inside2) {
        return 1;
    }

    /*
     * Both points are outside the rectangle, but still need to check
     * for intersections between the line and the rectangle.  Horizontal
     * and vertical lines are particularly easy, so handle them
     * separately.
     */

    if (end1Ptr[0] == end2Ptr[0]) {
        /*
         * Vertical line.
         */
    
        if (((end1Ptr[1] >= rectPtr[1]) ^ (end2Ptr[1] >= rectPtr[1]))
                && (end1Ptr[0] >= rectPtr[0])
                && (end1Ptr[0] <= rectPtr[2])) {
            return 0;
        }
    } else if (end1Ptr[1] == end2Ptr[1]) {
        /*
         * Horizontal line.
         */
    
        if (((end1Ptr[0] >= rectPtr[0]) ^ (end2Ptr[0] >= rectPtr[0]))
                && (end1Ptr[1] >= rectPtr[1])
                && (end1Ptr[1] <= rectPtr[3])) {
            return 0;
        }
    } else {
        double m, x, y, low, high;
    
        /*
         * Diagonal line.  Compute slope of line and use
         * for intersection checks against each of the
         * sides of the rectangle: left, right, bottom, top.
         */
    
        m = (end2Ptr[1] - end1Ptr[1])/(end2Ptr[0] - end1Ptr[0]);
        if (end1Ptr[0] < end2Ptr[0]) {
            low = end1Ptr[0];  high = end2Ptr[0];
        } else {
            low = end2Ptr[0]; high = end1Ptr[0];
        }
    
        /*
         * Left edge.
         */
    
        y = end1Ptr[1] + (rectPtr[0] - end1Ptr[0])*m;
        if ((rectPtr[0] >= low) && (rectPtr[0] <= high)
                && (y >= rectPtr[1]) && (y <= rectPtr[3])) {
            return 0;
        }
    
        /*
         * Right edge.
         */
    
        y += (rectPtr[2] - rectPtr[0])*m;
        if ((y >= rectPtr[1]) && (y <= rectPtr[3])
                && (rectPtr[2] >= low) && (rectPtr[2] <= high)) {
            return 0;
        }
    
        /*
         * Bottom edge.
         */
    
        if (end1Ptr[1] < end2Ptr[1]) {
            low = end1Ptr[1];  high = end2Ptr[1];
        } else {
            low = end2Ptr[1]; high = end1Ptr[1];
        }
        x = end1Ptr[0] + (rectPtr[1] - end1Ptr[1])/m;
        if ((x >= rectPtr[0]) && (x <= rectPtr[2])
                && (rectPtr[1] >= low) && (rectPtr[1] <= high)) {
            return 0;
        }
    
        /*
         * Top edge.
         */
    
        x += (rectPtr[3] - rectPtr[1])/m;
        if ((x >= rectPtr[0]) && (x <= rectPtr[2])
                && (rectPtr[3] >= low) && (rectPtr[3] <= high)) {
            return 0;
        }
    }
    return -1;
}
\f
/*
 *--------------------------------------------------------------
 *
 * TkPolygonToPoint --
 *
 *      Compute the distance from a point to a polygon.
 *
 * Results:
 *      The return value is 0.0 if the point referred to by
 *      pointPtr is within the polygon referred to by polyPtr
 *      and numPoints.  Otherwise the return value is the
 *      distance of the point from the polygon.
 *
 * Side effects:
 *      None.
 *
 *--------------------------------------------------------------
 */

double
TkPolygonToPoint(polyPtr, numPoints, pointPtr)
    double *polyPtr;            /* Points to an array coordinates for
                                 * closed polygon:  x0, y0, x1, y1, ...
                                 * The polygon may be self-intersecting. */
    int numPoints;              /* Total number of points at *polyPtr. */
    double *pointPtr;           /* Points to coords for point. */
{
    double bestDist;            /* Closest distance between point and
                                 * any edge in polygon. */
    int intersections;          /* Number of edges in the polygon that
                                 * intersect a ray extending vertically
                                 * upwards from the point to infinity. */
    int count;
    register double *pPtr;

    /*
     * Iterate through all of the edges in the polygon, updating
     * bestDist and intersections.
     *
     * TRICKY POINT:  when computing intersections, include left
     * x-coordinate of line within its range, but not y-coordinate.
     * Otherwise if the point lies exactly below a vertex we'll
     * count it as two intersections.
     */

    bestDist = 1.0e40;
    intersections = 0;

    for (count = numPoints, pPtr = polyPtr; count > 1; count--, pPtr += 2) {
        double x, y, dist;

        /*
         * Compute the point on the current edge closest to the point
         * and update the intersection count.  This must be done
         * separately for vertical edges, horizontal edges, and
         * other edges.
         */

        if (pPtr[2] == pPtr[0]) {

            /*
             * Vertical edge.
             */

            x = pPtr[0];
            if (pPtr[1] >= pPtr[3]) {
                y = MIN(pPtr[1], pointPtr[1]);
                y = MAX(y, pPtr[3]);
            } else {
                y = MIN(pPtr[3], pointPtr[1]);
                y = MAX(y, pPtr[1]);
            }
        } else if (pPtr[3] == pPtr[1]) {

            /*
             * Horizontal edge.
             */

            y = pPtr[1];
            if (pPtr[0] >= pPtr[2]) {
                x = MIN(pPtr[0], pointPtr[0]);
                x = MAX(x, pPtr[2]);
                if ((pointPtr[1] < y) && (pointPtr[0] < pPtr[0])
                        && (pointPtr[0] >= pPtr[2])) {
                    intersections++;
                }
            } else {
                x = MIN(pPtr[2], pointPtr[0]);
                x = MAX(x, pPtr[0]);
                if ((pointPtr[1] < y) && (pointPtr[0] < pPtr[2])
                        && (pointPtr[0] >= pPtr[0])) {
                    intersections++;
                }
            }
        } else {
            double m1, b1, m2, b2;
            int lower;                  /* Non-zero means point below line. */

            /*
             * The edge is neither horizontal nor vertical.  Convert the
             * edge to a line equation of the form y = m1*x + b1.  Then
             * compute a line perpendicular to this edge but passing
             * through the point, also in the form y = m2*x + b2.
             */

            m1 = (pPtr[3] - pPtr[1])/(pPtr[2] - pPtr[0]);
            b1 = pPtr[1] - m1*pPtr[0];
            m2 = -1.0/m1;
            b2 = pointPtr[1] - m2*pointPtr[0];
            x = (b2 - b1)/(m1 - m2);
            y = m1*x + b1;
            if (pPtr[0] > pPtr[2]) {
                if (x > pPtr[0]) {
                    x = pPtr[0];
                    y = pPtr[1];
                } else if (x < pPtr[2]) {
                    x = pPtr[2];
                    y = pPtr[3];
                }
            } else {
                if (x > pPtr[2]) {
                    x = pPtr[2];
                    y = pPtr[3];
                } else if (x < pPtr[0]) {
                    x = pPtr[0];
                    y = pPtr[1];
                }
            }
            lower = (m1*pointPtr[0] + b1) > pointPtr[1];
            if (lower && (pointPtr[0] >= MIN(pPtr[0], pPtr[2]))
                    && (pointPtr[0] < MAX(pPtr[0], pPtr[2]))) {
                intersections++;
            }
        }

        /*
         * Compute the distance to the closest point, and see if that
         * is the best distance seen so far.
         */

        dist = hypot(pointPtr[0] - x, pointPtr[1] - y);
        if (dist < bestDist) {
            bestDist = dist;
        }
    }

    /*
     * We've processed all of the points.  If the number of intersections
     * is odd, the point is inside the polygon.
     */

    if (intersections & 0x1) {
        return 0.0;
    }
    return bestDist;
}
\f
/*
 *--------------------------------------------------------------
 *
 * TkPolygonToArea --
 *
 *      Determine whether a polygon lies entirely inside, entirely
 *      outside, or overlapping a given rectangular area.
 *
 * Results:
 *      -1 is returned if the polygon given by polyPtr and numPoints
 *      is entirely outside the rectangle given by rectPtr.  0 is
 *      returned if the polygon overlaps the rectangle, and 1 is
 *      returned if the polygon is entirely inside the rectangle.
 *
 * Side effects:
 *      None.
 *
 *--------------------------------------------------------------
 */

int
TkPolygonToArea(polyPtr, numPoints, rectPtr)
    double *polyPtr;            /* Points to an array coordinates for
                                 * closed polygon:  x0, y0, x1, y1, ...
                                 * The polygon may be self-intersecting. */
    int numPoints;              /* Total number of points at *polyPtr. */
    register double *rectPtr;   /* Points to coords for rectangle, in the
                                 * order x1, y1, x2, y2.  X1 and y1 must
                                 * be lower-left corner. */
{
    int state;                  /* State of all edges seen so far (-1 means
                                 * outside, 1 means inside, won't ever be
                                 * 0). */
    int count;
    register double *pPtr;

    /*
     * Iterate over all of the edges of the polygon and test them
     * against the rectangle.  Can quit as soon as the state becomes
     * "intersecting".
     */

    state = TkLineToArea(polyPtr, polyPtr+2, rectPtr);
    if (state == 0) {
        return 0;
    }
    for (pPtr = polyPtr+2, count = numPoints-1; count >= 2;
            pPtr += 2, count--) {
        if (TkLineToArea(pPtr, pPtr+2, rectPtr) != state) {
            return 0;
        }
    }

    /*
     * If all of the edges were inside the rectangle we're done.
     * If all of the edges were outside, then the rectangle could
     * still intersect the polygon (if it's entirely enclosed).
     * Call TkPolygonToPoint to figure this out.
     */

    if (state == 1) {
        return 1;
    }
    if (TkPolygonToPoint(polyPtr, numPoints, rectPtr) == 0.0) {
        return 0;
    }
    return -1;
}
\f
/*
 *--------------------------------------------------------------
 *
 * TkOvalToPoint --
 *
 *      Computes the distance from a given point to a given
 *      oval, in canvas units.
 *
 * Results:
 *      The return value is 0 if the point given by *pointPtr is
 *      inside the oval.  If the point isn't inside the
 *      oval then the return value is approximately the distance
 *      from the point to the oval.  If the oval is filled, then
 *      anywhere in the interior is considered "inside";  if
 *      the oval isn't filled, then "inside" means only the area
 *      occupied by the outline.
 *
 * Side effects:
 *      None.
 *
 *--------------------------------------------------------------
 */

        /* ARGSUSED */
double
TkOvalToPoint(ovalPtr, width, filled, pointPtr)
    double ovalPtr[4];          /* Pointer to array of four coordinates
                                 * (x1, y1, x2, y2) defining oval's bounding
                                 * box. */
    double width;               /* Width of outline for oval. */
    int filled;                 /* Non-zero means oval should be treated as
                                 * filled;  zero means only consider outline. */
    double pointPtr[2];         /* Coordinates of point. */
{
    double xDelta, yDelta, scaledDistance, distToOutline, distToCenter;

    /*
     * Compute the distance between the center of the oval and the
     * point in question, using a coordinate system where the oval
     * has been transformed to a circle with unit radius.
     */

    xDelta = (pointPtr[0] - (ovalPtr[0] + ovalPtr[2])/2.0);
    yDelta = (pointPtr[1] - (ovalPtr[1] + ovalPtr[3])/2.0);
    distToCenter = hypot(xDelta, yDelta);
    scaledDistance = hypot(xDelta / ((ovalPtr[2] + width - ovalPtr[0])/2.0),
            yDelta / ((ovalPtr[3] + width - ovalPtr[1])/2.0));


    /*
     * If the scaled distance is greater than 1 then it means no
     * hit.  Compute the distance from the point to the edge of
     * the circle, then scale this distance back to the original
     * coordinate system.
     *
     * Note: this distance isn't completely accurate.  It's only
     * an approximation, and it can overestimate the correct
     * distance when the oval is eccentric.
     */

    if (scaledDistance > 1.0) {
        return (distToCenter/scaledDistance) * (scaledDistance - 1.0);
    }

    /*
     * Scaled distance less than 1 means the point is inside the
     * outer edge of the oval.  If this is a filled oval, then we
     * have a hit.  Otherwise, do the same computation as above
     * (scale back to original coordinate system), but also check
     * to see if the point is within the width of the outline.
     */

    if (filled) {
        return 0.0;
    }
    distToOutline = (distToCenter/scaledDistance) * (1.0 - scaledDistance)
            - width;
    if (distToOutline < 0.0) {
        return 0.0;
    }
    return distToOutline;
}
\f
/*
 *--------------------------------------------------------------
 *
 * TkOvalToArea --
 *
 *      Determine whether an oval lies entirely inside, entirely
 *      outside, or overlapping a given rectangular area.
 *
 * Results:
 *      -1 is returned if the oval described by ovalPtr is entirely
 *      outside the rectangle given by rectPtr.  0 is returned if the
 *      oval overlaps the rectangle, and 1 is returned if the oval
 *      is entirely inside the rectangle.
 *
 * Side effects:
 *      None.
 *
 *--------------------------------------------------------------
 */

int
TkOvalToArea(ovalPtr, rectPtr)
    register double *ovalPtr;   /* Points to coordinates definining the
                                 * bounding rectangle for the oval: x1, y1,
                                 * x2, y2.  X1 must be less than x2 and y1
                                 * less than y2. */
    register double *rectPtr;   /* Points to coords for rectangle, in the
                                 * order x1, y1, x2, y2.  X1 and y1 must
                                 * be lower-left corner. */
{
    double centerX, centerY, radX, radY, deltaX, deltaY;

    /*
     * First, see if oval is entirely inside rectangle or entirely
     * outside rectangle.
     */

    if ((rectPtr[0] <= ovalPtr[0]) && (rectPtr[2] >= ovalPtr[2])
            && (rectPtr[1] <= ovalPtr[1]) && (rectPtr[3] >= ovalPtr[3])) {
        return 1;
    }
    if ((rectPtr[2] < ovalPtr[0]) || (rectPtr[0] > ovalPtr[2])
            || (rectPtr[3] < ovalPtr[1]) || (rectPtr[1] > ovalPtr[3])) {
        return -1;
    }

    /*
     * Next, go through the rectangle side by side.  For each side
     * of the rectangle, find the point on the side that is closest
     * to the oval's center, and see if that point is inside the
     * oval.  If at least one such point is inside the oval, then
     * the rectangle intersects the oval.
     */

    centerX = (ovalPtr[0] + ovalPtr[2])/2;
    centerY = (ovalPtr[1] + ovalPtr[3])/2;
    radX = (ovalPtr[2] - ovalPtr[0])/2;
    radY = (ovalPtr[3] - ovalPtr[1])/2;

    deltaY = rectPtr[1] - centerY;
    if (deltaY < 0.0) {
        deltaY = centerY - rectPtr[3];
        if (deltaY < 0.0) {
            deltaY = 0;
        }
    }
    deltaY /= radY;
    deltaY *= deltaY;

    /*
     * Left side:
     */

    deltaX = (rectPtr[0] - centerX)/radX;
    deltaX *= deltaX;
    if ((deltaX + deltaY) <= 1.0) {
        return 0;
    }

    /*
     * Right side:
     */

    deltaX = (rectPtr[2] - centerX)/radX;
    deltaX *= deltaX;
    if ((deltaX + deltaY) <= 1.0) {
        return 0;
    }

    deltaX = rectPtr[0] - centerX;
    if (deltaX < 0.0) {
        deltaX = centerX - rectPtr[2];
        if (deltaX < 0.0) {
            deltaX = 0;
        }
    }
    deltaX /= radX;
    deltaX *= deltaX;

    /*
     * Bottom side:
     */

    deltaY = (rectPtr[1] - centerY)/radY;
    deltaY *= deltaY;
    if ((deltaX + deltaY) < 1.0) {
        return 0;
    }

    /*
     * Top side:
     */

    deltaY = (rectPtr[3] - centerY)/radY;
    deltaY *= deltaY;
    if ((deltaX + deltaY) < 1.0) {
        return 0;
    }

    return -1;
}
\f
/*
 *--------------------------------------------------------------
 *
 * TkIncludePoint --
 *
 *      Given a point and a generic canvas item header, expand
 *      the item's bounding box if needed to include the point.
 *
 * Results:
 *      None.
 *
 * Side effects:
 *      The boudn.
 *
 *--------------------------------------------------------------
 */

        /* ARGSUSED */
void
TkIncludePoint(canvasPtr, itemPtr, pointPtr)
    Tk_Canvas *canvasPtr;               /* Canvas containing item. */
    register Tk_Item *itemPtr;          /* Item whose bounding box is
                                         * being calculated. */
    double *pointPtr;                   /* Address of two doubles giving
                                         * x and y coordinates of point. */
{
    int tmp;

    tmp = pointPtr[0] + 0.5;
    if (tmp < itemPtr->x1) {
        itemPtr->x1 = tmp;
    }
    if (tmp > itemPtr->x2) {
        itemPtr->x2 = tmp;
    }
    tmp = pointPtr[1] + 0.5;
    if (tmp < itemPtr->y1) {
        itemPtr->y1 = tmp;
    }
    if (tmp > itemPtr->y2) {
        itemPtr->y2 = tmp;
    }
}
\f
/*
 *--------------------------------------------------------------
 *
 * TkBezierScreenPoints --
 *
 *      Given four control points, create a larger set of XPoints
 *      for a Bezier spline based on the points.
 *
 * Results:
 *      The array at *xPointPtr gets filled in with numSteps XPoints
 *      corresponding to the Bezier spline defined by the four 
 *      control points.  Note:  no output point is generated for the
 *      first input point, but an output point *is* generated for
 *      the last input point.
 *
 * Side effects:
 *      None.
 *
 *--------------------------------------------------------------
 */

void
TkBezierScreenPoints(canvasPtr, control, numSteps, xPointPtr)
    Tk_Canvas *canvasPtr;               /* Canvas in which curve is to be
                                         * drawn. */
    double control[];                   /* Array of coordinates for four
                                         * control points:  x0, y0, x1, y1,
                                         * ... x3 y3. */
    int numSteps;                       /* Number of curve points to
                                         * generate.  */
    register XPoint *xPointPtr;         /* Where to put new points. */
{
    int i;
    double u, u2, u3, t, t2, t3;

    for (i = 1; i <= numSteps; i++, xPointPtr++) {
        t = ((double) i)/((double) numSteps);
        t2 = t*t;
        t3 = t2*t;
        u = 1.0 - t;
        u2 = u*u;
        u3 = u2*u;
        xPointPtr->x = SCREEN_X(canvasPtr, (control[0]*u3
                + 3.0 * (control[2]*t*u2 + control[4]*t2*u) + control[6]*t3));
        xPointPtr->y = SCREEN_Y(canvasPtr, (control[1]*u3
                + 3.0 * (control[3]*t*u2 + control[5]*t2*u) + control[7]*t3));
    }
}
\f
/*
 *--------------------------------------------------------------
 *
 * TkBezierPoints --
 *
 *      Given four control points, create a larger set of points
 *      for a Bezier spline based on the points.
 *
 * Results:
 *      The array at *coordPtr gets filled in with 2*numSteps
 *      coordinates, which correspond to the Bezier spline defined
 *      by the four control points.  Note:  no output point is
 *      generated for the first input point, but an output point
 *      *is* generated for the last input point.
 *
 * Side effects:
 *      None.
 *
 *--------------------------------------------------------------
 */

void
TkBezierPoints(control, numSteps, coordPtr)
    double control[];                   /* Array of coordinates for four
                                         * control points:  x0, y0, x1, y1,
                                         * ... x3 y3. */
    int numSteps;                       /* Number of curve points to
                                         * generate.  */
    register double *coordPtr;          /* Where to put new points. */
{
    int i;
    double u, u2, u3, t, t2, t3;

    for (i = 1; i <= numSteps; i++, coordPtr += 2) {
        t = ((double) i)/((double) numSteps);
        t2 = t*t;
        t3 = t2*t;
        u = 1.0 - t;
        u2 = u*u;
        u3 = u2*u;
        coordPtr[0] = control[0]*u3
                + 3.0 * (control[2]*t*u2 + control[4]*t2*u) + control[6]*t3;
        coordPtr[1] = control[1]*u3
                + 3.0 * (control[3]*t*u2 + control[5]*t2*u) + control[7]*t3;
    }
}
\f
/*
 *--------------------------------------------------------------
 *
 * TkMakeBezierCurve --
 *
 *      Given a set of points, create a new set of points that
 *      fit Bezier splines to the line segments connecting the
 *      original points.  Produces output points in either of two
 *      forms.
 *
 * Results:
 *      Either or both of the xPoints or dblPoints arrays are filled
 *      in.  The return value is the number of points placed in the
 *      arrays.  Note:  if the first and last points are the same, then
 *      a closed curve is generated.
 *
 * Side effects:
 *      None.
 *
 *--------------------------------------------------------------
 */

int
TkMakeBezierCurve(canvasPtr, pointPtr, numPoints, numSteps, xPoints, dblPoints)
    Tk_Canvas *canvasPtr;               /* Canvas in which curve is to be
                                         * drawn. */
    double *pointPtr;                   /* Array of input coordinates:  x0,
                                         * y0, x1, y1, etc.. */
    int numPoints;                      /* Number of points at pointPtr. */
    int numSteps;                       /* Number of steps to use for each
                                         * spline segments (determines
                                         * smoothness of curve). */
    XPoint xPoints[];                   /* Array of XPoints to fill in (e.g.
                                         * for display.  NULL means don't
                                         * fill in any XPoints. */
    double dblPoints[];                 /* Array of points to fill in as
                                         * doubles, in the form x0, y0,
                                         * x1, y1, ....  NULL means don't
                                         * fill in anything in this form. 
                                         * Caller must make sure that this
                                         * array has enough space. */
{
    int closed, outputPoints, i;
    int numCoords = numPoints*2;
    double control[8];

    /*
     * If the curve is a closed one then generate a special spline
     * that spans the last points and the first ones.  Otherwise
     * just put the first point into the output.
     */

    outputPoints = 0;
    if ((pointPtr[0] == pointPtr[numCoords-2])
            && (pointPtr[1] == pointPtr[numCoords-1])) {
        closed = 1;
        control[0] = 0.5*pointPtr[numCoords-4] + 0.5*pointPtr[0];
        control[1] = 0.5*pointPtr[numCoords-3] + 0.5*pointPtr[1];
        control[2] = 0.167*pointPtr[numCoords-4] + 0.833*pointPtr[0];
        control[3] = 0.167*pointPtr[numCoords-3] + 0.833*pointPtr[1];
        control[4] = 0.833*pointPtr[0] + 0.167*pointPtr[2];
        control[5] = 0.833*pointPtr[1] + 0.167*pointPtr[3];
        control[6] = 0.5*pointPtr[0] + 0.5*pointPtr[2];
        control[7] = 0.5*pointPtr[1] + 0.5*pointPtr[3];
        if (xPoints != NULL) {
            xPoints->x = SCREEN_X(canvasPtr, control[0]);
            xPoints->y = SCREEN_Y(canvasPtr, control[1]);
            TkBezierScreenPoints(canvasPtr, control, numSteps, xPoints+1);
            xPoints += numSteps+1;
        }
        if (dblPoints != NULL) {
            dblPoints[0] = control[0];
            dblPoints[1] = control[1];
            TkBezierPoints(control, numSteps, dblPoints+2);
            dblPoints += 2*(numSteps+1);
        }
        outputPoints += numSteps+1;
    } else {
        closed = 0;
        if (xPoints != NULL) {
            xPoints->x = SCREEN_X(canvasPtr, pointPtr[0]);
            xPoints->y = SCREEN_Y(canvasPtr, pointPtr[1]);
            xPoints += 1;
        }
        if (dblPoints != NULL) {
            dblPoints[0] = pointPtr[0];
            dblPoints[1] = pointPtr[1];
            dblPoints += 2;
        }
        outputPoints += 1;
    }

    for (i = 2; i < numPoints; i++, pointPtr += 2) {
        /*
         * Set up the first two control points.  This is done
         * differently for the first spline of an open curve
         * than for other cases.
         */

        if ((i == 2) && !closed) {
            control[0] = pointPtr[0];
            control[1] = pointPtr[1];
            control[2] = 0.333*pointPtr[0] + 0.667*pointPtr[2];
            control[3] = 0.333*pointPtr[1] + 0.667*pointPtr[3];
        } else {
            control[0] = 0.5*pointPtr[0] + 0.5*pointPtr[2];
            control[1] = 0.5*pointPtr[1] + 0.5*pointPtr[3];
            control[2] = 0.167*pointPtr[0] + 0.833*pointPtr[2];
            control[3] = 0.167*pointPtr[1] + 0.833*pointPtr[3];
        }

        /*
         * Set up the last two control points.  This is done
         * differently for the last spline of an open curve
         * than for other cases.
         */

        if ((i == (numPoints-1)) && !closed) {
            control[4] = .667*pointPtr[2] + .333*pointPtr[4];
            control[5] = .667*pointPtr[3] + .333*pointPtr[5];
            control[6] = pointPtr[4];
            control[7] = pointPtr[5];
        } else {
            control[4] = .833*pointPtr[2] + .167*pointPtr[4];
            control[5] = .833*pointPtr[3] + .167*pointPtr[5];
            control[6] = 0.5*pointPtr[2] + 0.5*pointPtr[4];
            control[7] = 0.5*pointPtr[3] + 0.5*pointPtr[5];
        }

        /*
         * If the first two points coincide, or if the last
         * two points coincide, then generate a single
         * straight-line segment by outputting the last control
         * point.
         */

        if (((pointPtr[0] == pointPtr[2]) && (pointPtr[1] == pointPtr[3]))
                || ((pointPtr[2] == pointPtr[4])
                && (pointPtr[3] == pointPtr[5]))) {
            if (xPoints != NULL) {
                xPoints[0].x = SCREEN_X(canvasPtr, control[6]);
                xPoints[0].y = SCREEN_Y(canvasPtr, control[7]);
                xPoints++;
            }
            if (dblPoints != NULL) {
                dblPoints[0] = control[6];
                dblPoints[1] = control[7];
                dblPoints += 2;
            }
            outputPoints += 1;
            continue;
        }

        /*
         * Generate a Bezier spline using the control points.
         */


        if (xPoints != NULL) {
            TkBezierScreenPoints(canvasPtr, control, numSteps, xPoints);
            xPoints += numSteps;
        }
        if (dblPoints != NULL) {
            TkBezierPoints(control, numSteps, dblPoints);
            dblPoints += 2*numSteps;
        }
        outputPoints += numSteps;
    }
    return outputPoints;
}
\f
/*
 *--------------------------------------------------------------
 *
 * TkGetMiterPoints --
 *
 *      Given three points forming an angle, compute the
 *      coordinates of the inside and outside points of
 *      the mitered corner formed by a line of a given
 *      width at that angle.
 *
 * Results:
 *      If the angle formed by the three points is less than
 *      11 degrees then 0 is returned and m1 and m2 aren't
 *      modified.  Otherwise 1 is returned and the points at
 *      m1 and m2 are filled in with the positions of the points
 *      of the mitered corner.
 *
 * Side effects:
 *      None.
 *
 *--------------------------------------------------------------
 */

int
TkGetMiterPoints(p1, p2, p3, width, m1, m2)
    double p1[];                /* Points to x- and y-coordinates of point
                                 * before vertex. */
    double p2[];                /* Points to x- and y-coordinates of vertex
                                 * for mitered joint. */
    double p3[];                /* Points to x- and y-coordinates of point
                                 * after vertex. */
    double width;               /* Width of line.  */
    double m1[];                /* Points to place to put "left" vertex
                                 * point (see as you face from p1 to p2). */
    double m2[];                /* Points to place to put "right" vertex
                                 * point. */
{
    double theta1;              /* Angle of segment p2-p1. */
    double theta2;              /* Angle of segment p2-p3. */
    double theta;               /* Angle between line segments (angle
                                 * of joint). */
    double theta3;              /* Angle that bisects theta1 and
                                 * theta2 and points to m1. */
    double dist;                /* Distance of miter points from p2. */
    double deltaX, deltaY;      /* X and y offsets cooresponding to
                                 * dist (fudge factors for bounding
                                 * box). */
    static float elevenDegrees = (11.0*2.0*PI)/360.0;

    if (p2[1] == p1[1]) {
        theta1 = (p2[0] < p1[0]) ? 0 : PI;
    } else if (p2[0] == p1[0]) {
        theta1 = (p2[1] < p1[1]) ? PI/2.0 : -PI/2.0;
    } else {
        theta1 = atan2(p1[1] - p2[1], p1[0] - p2[0]);
    }
    if (p3[1] == p2[1]) {
        theta2 = (p3[0] > p2[0]) ? 0 : PI;
    } else if (p3[0] == p2[0]) {
        theta2 = (p3[1] > p2[1]) ? PI/2.0 : -PI/2.0;
    } else {
        theta2 = atan2(p3[1] - p2[1], p3[0] - p2[0]);
    }
    theta = theta1 - theta2;
    if (theta > PI) {
        theta -= 2*PI;
    } else if (theta < -PI) {
        theta += 2*PI;
    }
    if ((theta < elevenDegrees) && (theta > -elevenDegrees)) {
        return 0;
    }
    dist = 0.5*width/sin(0.5*theta);
    if (dist < 0.0) {
        dist = -dist;
    }

    /*
     * Compute theta3 (make sure that it points to the left when
     * looking from p1 to p2).
     */

    theta3 = (theta1 + theta2)/2.0;
    if (sin(theta3 - (theta1 + PI)) < 0.0) {
        theta3 += PI;
    }
    deltaX = dist*cos(theta3);
    m1[0] = p2[0] + deltaX;
    m2[0] = p2[0] - deltaX;
    deltaY = dist*sin(theta3);
    m1[1] = p2[1] + deltaY;
    m2[1] = p2[1] - deltaY;
    return 1;
}
\f
/*
 *--------------------------------------------------------------
 *
 * TkGetButtPoints --
 *
 *      Given two points forming a line segment, compute the
 *      coordinates of two endpoints of a rectangle formed by
 *      bloating the line segment until it is width units wide.
 *
 * Results:
 *      There is no return value.  M1 and m2 are filled in to
 *      correspond to m1 and m2 in the diagram below:
 *
 *                 ----------------* m1
 *                                 |
 *              p1 *---------------* p2
 *                                 |
 *                 ----------------* m2
 *
 *      M1 and m2 will be W units apart, with p2 centered between
 *      them and m1-m2 perpendicular to p1-p2.  However, if
 *      "project" is true then m1 and m2 will be as follows:
 *
 *                 -------------------* m1
 *                                p2  |
 *              p1 *---------------*  |
 *                                    |
 *                 -------------------* m2
 *
 *      In this case p2 will be width/2 units from the segment m1-m2.
 *
 * Side effects:
 *      None.
 *
 *--------------------------------------------------------------
 */

void
TkGetButtPoints(p1, p2, width, project, m1, m2)
    double p1[];                /* Points to x- and y-coordinates of point
                                 * before vertex. */
    double p2[];                /* Points to x- and y-coordinates of vertex
                                 * for mitered joint. */
    double width;               /* Width of line.  */
    int project;                /* Non-zero means project p2 by an additional
                                 * width/2 before computing m1 and m2. */
    double m1[];                /* Points to place to put "left" result
                                 * point, as you face from p1 to p2. */
    double m2[];                /* Points to place to put "right" result
                                 * point. */
{
    double length;              /* Length of p1-p2 segment. */
    double deltaX, deltaY;      /* Increments in coords. */

    width *= 0.5;
    length = hypot(p2[0] - p1[0], p2[1] - p1[1]);
    if (length == 0.0) {
        m1[0] = m2[0] = p2[0];
        m1[1] = m2[1] = p2[1];
    } else {
        deltaX = -width * (p2[1] - p1[1]) / length;
        deltaY = width * (p2[0] - p1[0]) / length;
        m1[0] = p2[0] + deltaX;
        m2[0] = p2[0] - deltaX;
        m1[1] = p2[1] + deltaY;
        m2[1] = p2[1] - deltaY;
        if (project) {
            m1[0] += deltaY;
            m2[0] += deltaY;
            m1[1] -= deltaX;
            m2[1] -= deltaX;
        }
    }
}